x^2+x-12+3=x^2

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Solution for x^2+x-12+3=x^2 equation: 



x^2+x-12+3=x^2

We move all terms to the left:

x^2+x-12+3-(x^2)=0

determiningTheFunctionDomain
x^2-x^2+x-12+3=0

We add all the numbers together, and all the variables

x-9=0

We move all terms containing x to the left, all other terms to the right

x=9

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